COMEDK · Maths · 27. Application of Derivatives
If the tangent to the curve \(2 y^{3}=a x^{2}+x^{3}\) at the point \((a, a)\) cuts off intercepts \(\alpha\) and \(\beta\) on the coordinate axes, where \(\alpha^{2}+\beta^{2}=61\), then the value of \(a\) is equal to
- A 25
- B 36
- C \(\pm 30\)
- D \(\pm 40\)
Answer & Solution
Correct Answer
(C) \(\pm 30\)
Step-by-step Solution
Detailed explanation
Given, equation of curve is \(2 y^{3}=a x^{2}+x^{3}\) \(\Rightarrow \quad 6 y^{2} \frac{d y}{d x}=2 a x+3 x^{2}\) \(\Rightarrow \quad \frac{d y}{d x}=\frac{2 a x+3 x^{2}}{6 y^{2}}\)…
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