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COMEDK · Maths · 27. Application of Derivatives

If the tangent to the curve \(2 y^{3}=a x^{2}+x^{3}\) at the point \((a, a)\) cuts off intercepts \(\alpha\) and \(\beta\) on the coordinate axes, where \(\alpha^{2}+\beta^{2}=61\), then the value of \(a\) is equal to

  1. A 25
  2. B 36
  3. C \(\pm 30\)
  4. D \(\pm 40\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\pm 30\)

Step-by-step Solution

Detailed explanation

Given, equation of curve is \(2 y^{3}=a x^{2}+x^{3}\) \(\Rightarrow \quad 6 y^{2} \frac{d y}{d x}=2 a x+3 x^{2}\) \(\Rightarrow \quad \frac{d y}{d x}=\frac{2 a x+3 x^{2}}{6 y^{2}}\)…