COMEDK · Maths · 34. Three Dimensional Geometry
If the straight lines \(\dfrac{x-2}{1}=\dfrac{y-3}{1}=\dfrac{z-4}{-t}\) and \(\dfrac{x-1}{t}=\dfrac{y-4}{2}=\dfrac{z-5}{1}\) are intersecting then \(t\) can have
- A Any number of values
- B Exactly one value
- C Exactly three values
- D Exactly two values
Answer & Solution
Correct Answer
(D) Exactly two values
Step-by-step Solution
Detailed explanation
The given lines are \(L_1: \dfrac{x-2}{1} = \dfrac{y-3}{1} = \dfrac{z-4}{-t} = \lambda\) and \(L_2: \dfrac{x-1}{t} = \dfrac{y-4}{2} = \dfrac{z-5}{1} = \mu\). The general points on the lines are \(P_1 = (2+\lambda, 3+\lambda, 4-t\lambda)\) and \(P_2 = (1+t\mu, 4+2\mu, 5+\mu)\).…
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