COMEDK · Maths · 21. Matrices
\(\text { If the matrix } A=\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right) \text { then } A^{n+1}=\)
- A \(2^n\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right)\) - B \(2 n\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right)\) - C \(2\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right)\) - D \(2^{n+1}\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right)\)
Answer & Solution
Correct Answer
(A) \(2^n\left(\begin{array}{cc}
1 & -1 \\
-1 & 1
\end{array}\right)\)
Step-by-step Solution
Detailed explanation
Given \(A = \begin{pmatrix} 1 & -1 \\ -1 & 1 \end{pmatrix}\). Calculate \(A^2\):…
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