COMEDK · Maths · 12. Circle
If the length of the tangent from any point on the circle \((x-3)^{2}+(y+2)^{2}=5 r^{2}\) to the circle \((x-3)^{2}+(y+2)^{2}=r^{2}\) is 16 units, then the area between the two circles in sq units is
- A \(16 \pi\)
- B \(8 \pi\)
- C \(4 \pi\)
- D \(256 \pi\)
Answer & Solution
Correct Answer
(D) \(256 \pi\)
Step-by-step Solution
Detailed explanation
Let point \(P\left(x_{1}, y_{1}\right)\) be any point on the circle, therefore it satisfy the circle \(\left(x_{1}-3\right)^{2}+\left(y_{1}+2\right)^{2}=5 r^{2}...(i)\) The length of the tangent drawn from point \(p\left(x_{1}, y_{1}\right)\) to the circle…
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