COMEDK · Maths · 27. Application of Derivatives
If the function \(f(x)=\mu \sin x+\dfrac{1}{3} \sin 3 x\) has its derivative equal to zero at \(x=\dfrac{\pi}{3}\), then the value of ' \(\mu\) ' is
- A \(1\)
- B \(-1\)
- C \(2\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
The given function is \(f(x) = \mu \sin x + \dfrac{1}{3} \sin 3x\). The derivative of the function is \(f'(x) = \dfrac{d}{dx} (\mu \sin x + \dfrac{1}{3} \sin 3x) = \mu \cos x + \dfrac{1}{3} \cos 3x \times 3 = \mu \cos x + \cos 3x\). It is given that \(f'(x) = 0\) at…
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