COMEDK · Maths · 10. Straight Lines
If the equation of pair of lines \(y=m_1 x\) and \(y=m_2 x\) can be written as \(\left(y-m_1 x\right)\) \(\left(y-m_2 x\right)=0\). Then the equation of pair of the angle bisector of the lines \(5 x^2+2 x y+3 y^2=0\) is
- A \(x^2-4 x y-y^2=0\)
- B \(x^2-2 x y-y^2=0\)
- C \(x^2-8 x y-y^2=0\)
- D \(x^2-6 x y-y^2=0\)
Answer & Solution
Correct Answer
(B) \(x^2-2 x y-y^2=0\)
Step-by-step Solution
Detailed explanation
If \(L \equiv a x^2+b y^2+2 h x y=0\) Then equation of pair of angle bisector is \(\frac{x^2-y^2}{a-b}=\frac{x y}{h}\) \(\therefore\) Equation of pair of angle bisector of \(5 x^2+2 x y+3 y^2=0\) is…
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