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COMEDK · Maths · 27. Application of Derivatives

If the curve \(y=2 x^{3}+a x^{2}+b x+c\) passes through the origin and the tangents drawn to it at \(x=-1\) and \(x=2\) are parallel to the \(X\)-axis, then the values of \(a, b\) and \(c\) are respectively,

  1. A \(3,-12\) and 0
  2. B \(-3,12\) and 0
  3. C \(-3,-12\) and 0
  4. D \(12,-3\) and 0
Verified Solution

Answer & Solution

Correct Answer

(C) \(-3,-12\) and 0

Step-by-step Solution

Detailed explanation

\(y=2 x^{3}+a x^{2}+b x+c...(i)\) Since, it passes through \((0,0)\), \(0=2(0)+a(0)+b(0)+c\) \(\begin{aligned} c &=0 ...(ii)\\ \frac{d y}{d x} &=6 x^{2}+2 a x+b \end{aligned}\) Since, tangents at \(x=-1\) and \(x=2\) are parallel to \(X\)-axis.…