COMEDK · Maths · 28. Indefinite Integration
If the area under the curve \(y=\sqrt{a^2-x^2}\) included between the lines \(x=0\) and \(x=a\) is 4 sq units. Then the value of ' \(a\) ' is
- A \(\dfrac{2}{\sqrt{\pi}}\)
- B \(\dfrac{4}{\pi}\)
- C \(\dfrac{16}{\sqrt{\pi}}\)
- D \(\dfrac{4}{\sqrt{\pi}}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{4}{\sqrt{\pi}}\)
Step-by-step Solution
Detailed explanation
The area under the curve \(y = \sqrt{a^2 - x^2}\) from \(x = 0\) to \(x = a\) is given by the integral \(A = \int_{0}^{a} \sqrt{a^2 - x^2} dx\). Using the standard integral formula…
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