COMEDK · Maths · 22. Determinants
If the area of the triangle with vertices \((x, 0)\), \((1,1)\) and \((0,2)\) is \(4\) sq units, then the value of \(x\) is
- A \(-2\)
- B \(-4\)
- C \(-6\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(-6\)
Step-by-step Solution
Detailed explanation
We have, \(\frac{1}{2}\left|\begin{array}{lll}x & 0 & 1 \\ 1 & 1 & 1 \\ 0 & 2 & 1\end{array}\right|=\pm 4\) \(\Rightarrow \quad x(1-2)+1(2-0)=\pm 8\) \(\Rightarrow \quad-x+2=\pm 8\) \(\Rightarrow \quad \forall=2 \pm 8 \Rightarrow x=10,-6\)
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