COMEDK · Maths · 19. Properties of Triangles
If the angles of a triangle are in the ratio \(3: 4: 5\), then the sides are in the ratio
- A \(3: 4: 5\)
- B \(2: \sqrt{3}: \sqrt{3}+1\)
- C \(\sqrt{2}: \sqrt{6}: \sqrt{3}+1\)
- D \(2: \sqrt{6}: \sqrt{3}+1\)
Answer & Solution
Correct Answer
(D) \(2: \sqrt{6}: \sqrt{3}+1\)
Step-by-step Solution
Detailed explanation
Let the angles of triangle are \(3 \theta, 4 \theta, 5 \theta\). As we know that, \(\angle A+\angle B+\angle C=180^{\circ}\) \(\begin{array}{ll}\Rightarrow & 3 \theta+4 \theta+5 \theta=180^{\circ} \\ \Rightarrow & 12 \theta=180^{\circ} \Rightarrow \theta=15^{\circ}\end{array}\)…
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