COMEDK · Maths · 36. Probability
\(\text { If } P(B)=\dfrac{3}{5} \quad P(A / B)=\dfrac{1}{2} \text { and } P(A \cup B)=\dfrac{4}{5} \text { then } P(A \cup B)^{\prime}+P\left(A^{\prime} \cup B\right)=\)
- A 1
- B \(\dfrac{1}{5}\)
- C \(\dfrac{1}{2}\)
- D \(\dfrac{4}{5}\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Given \(P(B) = \dfrac{3}{5}\), \(P(A|B) = \dfrac{1}{2}\), and \(P(A \cup B) = \dfrac{4}{5}\). Using the definition of conditional probability, \(P(A \cap B) = P(A|B) \times P(B) = \dfrac{1}{2} \times \dfrac{3}{5} = \dfrac{3}{10}\). Using the addition rule…
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