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COMEDK · Maths · 24. Functions

If \(n(A)=n(B)-m\), then the number of possiblc bijection from \(A\) to \(B\) is

  1. A \(m\)
  2. B \(m^{2}\)
  3. C \(m\) !
  4. D \(2 \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(m\) !

Step-by-step Solution

Detailed explanation

If set \(A\) and \(B\) has \(m\) elements, then the number of bijections from \(A\) to \(B\) is the total number of arrangements of \(n\) distinct items taken all at a time, i.e. \(m !\).