ExamBro
ExamBro
COMEDK · Maths · 7. Binomial Theorem

If \({ }^{\mathrm{n}+2} \mathrm{C}_8:{ }^{\mathrm{n}-2} \mathrm{P}_4=57: 16\), then ' n ' is

  1. A 21
  2. B 17
  3. C 19
  4. D 20
Verified Solution

Answer & Solution

Correct Answer

(C) 19

Step-by-step Solution

Detailed explanation

The given ratio is \(\dfrac{^{n+2}C_{8}}{^{n-2}P_{4}} = \dfrac{57}{16}\). Using the definitions \(^{n}C_{r} = \dfrac{n!}{r!(n-r)!}\) and \(^{n}P_{r} = \dfrac{n!}{(n-r)!}\), we have: \(\dfrac{(n+2)!}{8!(n-6)!} \times \dfrac{(n-6)!}{(n-2)!} = \dfrac{57}{16}\) Simplifying the…