COMEDK · Maths · 3. Complex Number
If \(\omega\) is a cube root of unity, then the value of \(\operatorname{determinant}\left|\begin{array}{ccc}1+\omega & \omega^{2} & \omega \\ \omega^{2}+\omega & -\omega & \omega^{2} \\ 1+\omega^{2} & \omega & \omega^{2}\end{array}\right|\) is equal to
- A \(1+\omega\)
- B \(1-\omega\)
- C 0
- D \(\omega^{2}\)
Answer & Solution
Correct Answer
(B) \(1-\omega\)
Step-by-step Solution
Detailed explanation
We have, \(\left|\begin{array}{ccc}1+\omega & \omega^{2} & \omega \\ \omega^{2}+\omega & -\omega & \omega^{2} \\ 1+\omega^{2} & \omega & \omega^{2}\end{array}\right|\)…
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