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COMEDK · Maths · 23. Inverse Trigonometric Functions

If in a \(\triangle A B C, \angle C=\frac{\pi}{2}\), then \(\tan ^{-1}\left(\frac{a}{b+c}\right)+\tan ^{-1}\left(\frac{b}{c+a}\right)=\)

  1. A \(\frac{\pi}{4}\)
  2. B \(\frac{\pi}{2}\)
  3. C \(\frac{\pi}{3}\)
  4. D None of these
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\pi}{4}\)

Step-by-step Solution

Detailed explanation

Given, \(\angle C=\frac{\pi}{2} \Rightarrow c^{2}=a^{2}+b^{2}\) \{by pythagoras \(\}\) Now, \(\tan ^{-1}\left(\frac{a}{b+c}\right)+\tan ^{-1}\left(\frac{b}{c+a}\right)\)…