COMEDK · Maths · 23. Inverse Trigonometric Functions
If in a \(\triangle A B C, \angle C=\frac{\pi}{2}\), then \(\tan ^{-1}\left(\frac{a}{b+c}\right)+\tan ^{-1}\left(\frac{b}{c+a}\right)=\)
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{3}\)
- D None of these
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
Given, \(\angle C=\frac{\pi}{2} \Rightarrow c^{2}=a^{2}+b^{2}\) \{by pythagoras \(\}\) Now, \(\tan ^{-1}\left(\frac{a}{b+c}\right)+\tan ^{-1}\left(\frac{b}{c+a}\right)\)…
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