COMEDK · Maths · 30. Definite Integration
\(\text { If } I_n=\int_\limits0^{\dfrac{\pi}{4}} \tan ^n x d x \text {, for } n \geq 2 \text {, then } I_n+I_{n-2}=\)
- A \(\dfrac{1}{n+1}\)
- B \(\dfrac{1}{n}\)
- C \(\dfrac{1}{n}+\dfrac{1}{n-2}\)
- D \(\dfrac{1}{n-1}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{1}{n-1}\)
Step-by-step Solution
Detailed explanation
Given \(I_n = \int_{0}^{\dfrac{\pi}{4}} \tan^{n} x dx\). Consider the sum \(I_n + I_{n-2} = \int_{0}^{\dfrac{\pi}{4}} \tan^{n} x dx + \int_{0}^{\dfrac{\pi}{4}} \tan^{n-2} x dx\). \(I_n + I_{n-2} = \int_{0}^{\dfrac{\pi}{4}} \tan^{n-2} x (\tan^{2} x + 1) dx\). Using the identity…
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