COMEDK · Maths · 30. Definite Integration
If \(f(x)\) is defined in \([-2,2]\) by \(f(x)=4 x^{2}-3 x+1\) and \(g(x)=\frac{f(-x)-f(x)}{\left(x^{2}+3\right)}\), then \(\int_{-2}^{2} g(x) d x=\)
- A 24
- B 0
- C \(-48\)
- D 64
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
Given that, \(f(x)=4 x^{2}-3 x+1\) \(g(x)=\frac{f(-x)-f(x)}{x^{2}+3}\) Therefore, \(g(x)=\frac{\left(4 x^{2}+3 x+1\right)-\left(4 x^{2}-3 x+1\right)}{x^{2}+3}=\frac{6 x}{x^{2}+3}\) Now, \(g(-x)=-\frac{6 x}{x^{2}+3}=g(x)\) which is an odd function. Thus,…
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