COMEDK · Maths · 28. Indefinite Integration
If \(\int f(x) d x=g(x)\), then \(\int f(x) g(x) d x=\)
- A \(\frac{1}{2} f^{2}(x)\)
- B \(\frac{1}{2} g^{2}(x)\)
- C \(\frac{1}{2}\left[g^{\prime}(x)\right]^{2}\)
- D \(f^{\prime}(x) g(x)\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} g^{2}(x)\)
Step-by-step Solution
Detailed explanation
We have, \(\int f(x) d x=g(x)\) \(\Rightarrow \quad f(x)=g^{\prime}(x)\) Now, let \(I=\int f(x) \cdot g(x) d x=\int g^{\prime}(x) g(x) d x\) Put \(g(x)=t\) \(\Rightarrow \quad g^{\prime}(x) d x=d t\) \(\therefore \quad I=\int t d t=\frac{t^{2}}{2}+C=\frac{1}{2}(g(x))^{2}+C\)
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