COMEDK · Maths · 22. Determinants
If \(\alpha, \beta, \gamma\) are the roots of \(x^{3}+a^{2} x+b=0\), then the value of \(\left|\begin{array}{lll}\alpha & \beta & \gamma \\ \beta & \gamma & \alpha \\ \gamma & \alpha & \beta\end{array}\right|\) is
- A \(-a^{3}\)
- B \(a^{3}-3 b\)
- C \(a^{3}\)
- D 0
Answer & Solution
Correct Answer
(D) 0
Step-by-step Solution
Detailed explanation
Given, equation is \(x^{3}+a^{2} x+b=0\) Since, \(\alpha, \beta, \gamma\) are its roots. \(\therefore\) Sum of roots \(=\alpha+\beta+\gamma=0 \quad \text{...(i)}\) Now,…
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