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COMEDK · Maths · 22. Determinants

If \(\alpha, \beta, \gamma\) are the roots of \(x^{3}+a^{2} x+b=0\), then the value of \(\left|\begin{array}{lll}\alpha & \beta & \gamma \\ \beta & \gamma & \alpha \\ \gamma & \alpha & \beta\end{array}\right|\) is

  1. A \(-a^{3}\)
  2. B \(a^{3}-3 b\)
  3. C \(a^{3}\)
  4. D 0
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Answer & Solution

Correct Answer

(D) 0

Step-by-step Solution

Detailed explanation

Given, equation is \(x^{3}+a^{2} x+b=0\) Since, \(\alpha, \beta, \gamma\) are its roots. \(\therefore\) Sum of roots \(=\alpha+\beta+\gamma=0 \quad \text{...(i)}\) Now,…