COMEDK · Maths · 10. Straight Lines
If a vertex of traingle is \((3,3)\) and the mid-points of two sides through this vertex are \(\left(2, \frac{3}{2}\right)\) and \(\left(4, \frac{3}{2}\right)\), then the centroid of the triangle is given by
- A \((1,3)\)
- B \((3,0)\)
- C \((3,1)\)
- D \((0,3)\)
Answer & Solution
Correct Answer
(C) \((3,1)\)
Step-by-step Solution
Detailed explanation
Let the vertices of \(\triangle A B C\) are \(A(3,3), B\left(x_{1}, y_{1}\right)\) and \(C\left(x_{2}, y_{2}\right)\). Now, \(\frac{x_{1}+3}{2}=2\) and \(\frac{y_{1}+3}{2}=\frac{3}{2}\) \(x_{1}+3=4\) and \(y_{1}+3=3\) \(x_{1}=1\) and \(y_{1}=0\) So, \(\quad B \equiv(1,0)\) and…
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