COMEDK · Maths · 36. Probability
If a number \(n\) is chosen at random from the set \(\{11,12,13, \ldots \ldots, 30\}\). Then, the probability that \(n\) is neither divisible by 3 nor divisible by 5 , is
- A \(\frac{7}{20}\)
- B \(\frac{9}{20}\)
- C \(\frac{11}{20}\)
- D \(\frac{13}{20}\)
Answer & Solution
Correct Answer
(C) \(\frac{11}{20}\)
Step-by-step Solution
Detailed explanation
Here, number which are divisible by either 3 or 5 are \(12,15,18,20,21,24,27,30\). \(\therefore\) Total numbers \(=9\) \(P(\) number either divisible by 3 or 5\()=\frac{9}{20}\) \(P\) (number neither divisible by 3 nor 5 ) \(=1-P\) (number either divisible by 3 or 5 )…
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