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COMEDK · Maths · 33. Vector Algebra

If \(\mathbf{a} \hat{\mathfrak{i}}=\mathbf{a}(\hat{\hat{i}}+\hat{\hat{j}})=\mathbf{a}(\hat{\mathbf{i}}+\hat{\hat{b}}+\hat{\mathbf{k}})=1\), then \(\mathbf{a}=\)

  1. A \(\hat{i}+\hat{j}\)
  2. B \(\hat{\mathrm{i}}-\hat{\mathrm{k}}\)
  3. C \(\hat{\hat{i}}\)
  4. D \(\hat{\mathrm{i}}+\hat{j}-\hat{\mathbf{i}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\hat{\hat{i}}\)

Step-by-step Solution

Detailed explanation

Let \(\mathbf{a}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}}\) Now, \(\mathbf{a} \cdot \hat{\mathbf{i}}=(x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}}) \cdot \hat{\mathbf{i}}=x\)…