COMEDK · Maths · 2. Quadratic Equation
If \(a, b, c\), and \(d\) are the roots of the equation \(x^{4}+2 x^{3}+3 x^{2}+4 x+5=0\), then \(1+a^{2}+b^{2}+c^{2}+d^{2}\) is equal to
- A \(-2\)
- B \(-1\)
- C 2
- D 1
Answer & Solution
Correct Answer
(B) \(-1\)
Step-by-step Solution
Detailed explanation
As, \[ \begin{gathered} (a+b+c+d)^{2}=a^{2}+b^{2}+c^{2}+d^{2} \\ +2(a b+b c+a d+b c+b d+c d) \\ \Rightarrow a^{2}+b^{2}+c^{2}+d^{2}=(a+b+c+d)^{2} \\ -2[a b+b c+a c+a d+b d+c d] \end{gathered} \] Now, as \(a, b, c, d\) are the roots of the equation. We have,…
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