COMEDK · Maths · 8. Trigonometric Ratios & Identities
If \(\cos (A-B)=\dfrac{3}{5}\) and \(\tan A \cdot \tan B=2\), then
- A \(\cos A \cdot \cos B=\dfrac{1}{5}\)
- B \(\sin A \cdot \sin B=-\dfrac{1}{5}\)
- C \(\cos A \cdot \cos B=-\dfrac{1}{5}\)
- D \(\sin A \cdot \sin B=\dfrac{1}{5}\)
Answer & Solution
Correct Answer
(A) \(\cos A \cdot \cos B=\dfrac{1}{5}\)
Step-by-step Solution
Detailed explanation
Given \(\cos(A-B) = \cos A \cos B + \sin A \sin B = \dfrac{3}{5}\). Also given \(\tan A \tan B = 2\), which implies \(\dfrac{\sin A \sin B}{\cos A \cos B} = 2\), so \(\sin A \sin B = 2 \cos A \cos B\). Substituting this into the first equation:…
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