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COMEDK · Maths · 33. Vector Algebra

\(\text { If }|\vec{a} \times \vec{b}|^2+|\vec{a} \cdot \vec{b}|^2=144 ~\&~|\vec{a}|=4 \text { then }|\vec{b}|=\)

  1. A 16
  2. B 8
  3. C 12
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(D) 3

Step-by-step Solution

Detailed explanation

Using the Lagrange identity for vectors, we have \(|\vec{a} \times \vec{b}|^2 + |\vec{a} \cdot \vec{b}|^2 = |\vec{a}|^2 |\vec{b}|^2\). Given that \(|\vec{a} \times \vec{b}|^2 + |\vec{a} \cdot \vec{b}|^2 = 144\), we substitute this into the identity:…