COMEDK · Maths · 33. Vector Algebra
\(\text { If }|\vec{a} \times \vec{b}|^2+|\vec{a} \cdot \vec{b}|^2=144 ~\&~|\vec{a}|=4 \text { then }|\vec{b}|=\)
- A 16
- B 8
- C 12
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
Using the Lagrange identity for vectors, we have \(|\vec{a} \times \vec{b}|^2 + |\vec{a} \cdot \vec{b}|^2 = |\vec{a}|^2 |\vec{b}|^2\). Given that \(|\vec{a} \times \vec{b}|^2 + |\vec{a} \cdot \vec{b}|^2 = 144\), we substitute this into the identity:…
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