COMEDK · Maths · 21. Matrices
If \(A=\left[\begin{array}{ll}2 & 2 \\ 3 & 4\end{array}\right]\), then \(A^{-1}\) equals to
- A \(\left[\begin{array}{cc}2 & 1 \\ -3 / 2 & -1\end{array}\right]\)
- B \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}-2 & 1 \\ 3 / 2 & -1\end{array}\right]\)
- D \(\left[\begin{array}{cc}-2 & -1 \\ 3 / 2 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Given, } A=\left[\begin{array}{ll} 2 & 2 \\ 3 & 4 \end{array}\right] \\ & \therefore \quad|A|=\left|\begin{array}{ll} 2 & 2 \\ 3 & 4 \end{array}\right|=2 \times 4-3 \times 2=8-6=2 \end{aligned} \] Now, \(A_{11}=4, A_{12}=-3, A_{21}=-2\) and…
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