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COMEDK · Maths · 21. Matrices

If \(A=\left[\begin{array}{ll}2 & 2 \\ 3 & 4\end{array}\right]\), then \(A^{-1}\) equals to

  1. A \(\left[\begin{array}{cc}2 & 1 \\ -3 / 2 & -1\end{array}\right]\)
  2. B \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)
  3. C \(\left[\begin{array}{cc}-2 & 1 \\ 3 / 2 & -1\end{array}\right]\)
  4. D \(\left[\begin{array}{cc}-2 & -1 \\ 3 / 2 & 1\end{array}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)

Step-by-step Solution

Detailed explanation

\[ \begin{aligned} & \text { Given, } A=\left[\begin{array}{ll} 2 & 2 \\ 3 & 4 \end{array}\right] \\ & \therefore \quad|A|=\left|\begin{array}{ll} 2 & 2 \\ 3 & 4 \end{array}\right|=2 \times 4-3 \times 2=8-6=2 \end{aligned} \] Now, \(A_{11}=4, A_{12}=-3, A_{21}=-2\) and…