COMEDK · Maths · 21. Matrices
If \(A=\left[\begin{array}{ll}2 & 2 \\ 3 & 4\end{array}\right]\), then \(A^{-1}\) equals to
- A \(\left[\begin{array}{cc}2 & 1 \\ -3 / 2 & -1\end{array}\right]\)
- B \(\left[\begin{array}{cc}-2 & -1 \\ 3 / 2 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}-2 & 1 \\ 3 / 2 & -1\end{array}\right]\)
- D \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{cc}2 & -1 \\ -3 / 2 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
Given the matrix \(A = \begin{bmatrix} 2 & 2 \\ 3 & 4 \end{bmatrix}\). The determinant of \(A\) is calculated as \(|A| = (2 \times 4) - (2 \times 3) = 8 - 6 = 2\). The inverse of a \(2 \times 2\) matrix \(A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}\) is given by…
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