COMEDK · Maths · 21. Matrices
If \(A=\left[\begin{array}{ll}1 & 2 \\ 0 & 1\end{array}\right]\), then \(A^{n}\) is
- A \(\left[\begin{array}{cc}1 & 2^{n}-2 \\ 0 & 1\end{array}\right]\)
- B \(\left[\begin{array}{cc}1 & n^{2} \\ 0 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}1 & 2 n \\ 0 & 1\end{array}\right]\)
- D \(\left[\begin{array}{cc}1 & n^{2} \\ 1 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{cc}1 & 2 n \\ 0 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
We have, \(A=\left[\begin{array}{ll}1 & 2 \\ 0 & 1\end{array}\right]\)…
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