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COMEDK · Maths · 22. Determinants

If \(A=\left[\begin{array}{cc}2-k & 2 \\ 1 & 3-k\end{array}\right]\) is a singular matrix, then the value of \(5 k-k^2\) is

  1. A 0
  2. B 6
  3. C -6
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(D) 4

Step-by-step Solution

Detailed explanation

A matrix \(A\) is singular if its determinant is zero, so \(\det(A) = 0\). Given \(A = \begin{bmatrix} 2-k & 2 \\ 1 & 3-k \end{bmatrix}\), the determinant is calculated as: \(\det(A) = (2-k)(3-k) - (2)(1) = 0\) Expanding the expression: \(6 - 2k - 3k + k^2 - 2 = 0\)…