COMEDK · Maths · 33. Vector Algebra
\(\text { If } \vec{a} \text { and } \vec{b} \text { are unit vectors, then the angle between } \vec{a} \text { and } \vec{b} \text { for which } a-\sqrt{2} \vec{b} \text { is a unit vector is }\)
- A \(\dfrac{\pi}{3}\)
- B \(\dfrac{\pi}{6}\)
- C \(\dfrac{\pi}{4}\)
- D \(\dfrac{\pi}{2}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
Given that \(\vec{a}\) and \(\vec{b}\) are unit vectors, we have \(|\vec{a}| = 1\) and \(|\vec{b}| = 1\). The vector \(\vec{a} - \sqrt{2}\vec{b}\) is a unit vector, which implies \(|\vec{a} - \sqrt{2}\vec{b}| = 1\). Squaring both sides, we get…
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