COMEDK · Maths · 8. Trigonometric Ratios & Identities
\(\text { If } \sin A=\dfrac{4}{5} \text { and } \cos B=\dfrac{-12}{13} \text { where } A \text { and } B \text { lie in first and third quadrant respectively. Then } \cos (A+B)=\)
- A \(\dfrac{-16}{65}\)
- B \(\dfrac{-56}{65}\)
- C \(\dfrac{16}{65}\)
- D \(\dfrac{56}{65}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{-16}{65}\)
Step-by-step Solution
Detailed explanation
Given \(\sin A = \dfrac{4}{5}\) and \(A\) is in the first quadrant, \(\cos A = \sqrt{1 - \sin^2 A} = \sqrt{1 - \left(\dfrac{4}{5}\right)^2} = \sqrt{1 - \dfrac{16}{25}} = \sqrt{\dfrac{9}{25}} = \dfrac{3}{5}\). Given \(\cos B = \dfrac{-12}{13}\) and \(B\) is in the third quadrant,…
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