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COMEDK · Maths · 33. Vector Algebra

If \(|\vec{a}|=2 \sqrt{2}\) and \(|\vec{b}|=3\) and angle between \(\vec{a}\) and \(\vec{b}\) is \(\dfrac{\pi}{4}\). If a parallelogram is constructed with adjacent sides \(\vec{p}=2 \vec{a}-3 \vec{b}\) and \(\vec{q}=\vec{a}+\vec{b}\) then the product of length of both the diagonals is

  1. A 6
  2. B \(60 \sqrt{2}\)
  3. C \(18 \sqrt{260}\)
  4. D \(12 \sqrt{26}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(12 \sqrt{26}\)

Step-by-step Solution

Detailed explanation

Given \(|\vec{a}| = 2\sqrt{2}\), \(|\vec{b}| = 3\), and the angle \(\theta = \dfrac{\pi}{4}\) between \(\vec{a}\) and \(\vec{b}\). The dot product is…