COMEDK · Maths · 21. Matrices
If \(A=\dfrac{1}{\pi}\left[\begin{array}{cc}\sin ^{-1} \dfrac{1}{2} & \tan ^{-1} \dfrac{x}{\pi} \\ \sin ^{-1} \dfrac{x}{\pi} & \cot ^{-1} \sqrt{3}\end{array}\right] \quad B=\dfrac{1}{\pi}\left[\begin{array}{cc}-\cos ^{-1} \dfrac{1}{2} & \tan ^{-1} \dfrac{x}{\pi} \\ \sin ^{-1} \dfrac{x}{\pi} & -\tan ^{-1} \sqrt{3}\end{array}\right]\) and I is an identity matrix of order \(2 \times 2\), then \(A-B=\)
- A 0
- B \(\dfrac{1}{2} \mathrm{I}\)
- C \(2 I\)
- D \(I\)
Answer & Solution
Correct Answer
(B) \(\dfrac{1}{2} \mathrm{I}\)
Step-by-step Solution
Detailed explanation
\(A - B = \dfrac{1}{\pi}\begin{bmatrix} \sin^{-1}\dfrac{1}{2} + \cos^{-1}\dfrac{1}{2} & 0 \\ 0 & \cot^{-1}\sqrt{3} + \tan^{-1}\sqrt{3} \end{bmatrix}\) Using identities: \(\sin^{-1}(y) + \cos^{-1}(y) = \dfrac{\pi}{2}\) and \(\tan^{-1}(y) + \cot^{-1}(y) = \dfrac{\pi}{2}\)…
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