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COMEDK · Maths · 1. Basic of Mathematics

If \(\log _{6} a+\log _{6} b+\log _{6} c=6\), where \(a, b\) and \(c\) are positive integers that form an increasing \(\mathrm{GP}\) and \(b-a\) is a square of an integer, then \(a+b+c=\)

  1. A 95
  2. B 99
  3. C 105
  4. D 111
Verified Solution

Answer & Solution

Correct Answer

(D) 111

Step-by-step Solution

Detailed explanation

We have, \(\log _{6} a b c=6 \Rightarrow a b c=6^{6}...(i)\) Let \(b=a r, c=a r^{2}\) Eq. (i), \(\quad a^{3} r^{3}=6^{6} \Rightarrow b-x^{n}=36\) \(b-a=36-a\) is square for \(a=35,32,27,20,11\)…