COMEDK · Maths · 3. Complex Number
If \((\sqrt{5}+\sqrt{3} i)^{33}=2^{49} z\), then modulus of the complex number \(z\) is equal to
- A 1
- B \(\sqrt{2}\)
- C \(2 \sqrt{2}\)
- D 4
Answer & Solution
Correct Answer
(B) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
We have, \((\sqrt{5}+\sqrt{3} i)^{33}=2^{49} z\) Taking modulus on both sides, we get…
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