COMEDK · Maths · 1. Basic of Mathematics
If \(\frac{3 x^{2}-2 x+4}{(x-1)^{6}}=\frac{A_{1}}{x+1}+\frac{A_{2}}{(x+1)^{2}}+\frac{A_{3}}{(x+1)^{3}}\) \(+\frac{A_{4}}{(x+1)^{4}}+\frac{A_{5}}{(x+1)^{5}}+\frac{A_{6}}{(x+1)^{6}}\), then \(\left(A_{1}+A_{2}+A_{2}-A_{4}-A_{6}\right)=\)
- A \((0,0)\)
- B \((-8,-12)\)
- C \((8,-12)\)
- D \((-8,12)\)
Answer & Solution
Correct Answer
(D) \((-8,12)\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} \frac{3 x^{2}-2 x+4}{(x-1)^{6}}=\frac{A_{1}}{x+1} &+\frac{A_{2}}{(x+1)^{2}}+\frac{A_{3}}{(x+1)^{3}} \\ &+\frac{A_{4}}{(x+1)^{4}}+\frac{A_{5}}{(x+1)^{5}}+\frac{A_{6}}{(x+1)^{6}} \ldots(\mathrm{i}) \end{aligned} \] Now, put \(x=0\) in Eq. (i), we get…
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