COMEDK · Maths · 27. Application of Derivatives
If 3 cm/s is the rate at which the side of an equilateral triangle increases, then the rate of change of area, when the side is 12 cm is:
- A \(18\sqrt{3} \ \text{cm}^2 / \text{s}\)
- B \(18 \ \text{cm}^2 / \text{s}\)
- C \(9\sqrt{3} \ \text{cm}^2 / \text{s}\)
- D \(6\sqrt{3} \ \text{cm}^2 / \text{s}\)
Answer & Solution
Correct Answer
(A) \(18\sqrt{3} \ \text{cm}^2 / \text{s}\)
Step-by-step Solution
Detailed explanation
Let the side of the equilateral triangle be \(a\) and its area be \(A\). The area of an equilateral triangle is given by \(A = \dfrac{\sqrt{3}}{4} a^2\). Differentiating with respect to time \(t\), we get:…
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