COMEDK · Maths · 30. Definite Integration
If \(\int_{\log 2}^{x} \frac{d y}{\sqrt{e^{y}-1}}=\frac{\pi}{6}\), then \(x\) is equal to
- A \(\log _{e} 4\)
- B \(\log _{e} 2\)
- C 4
- D 2
Answer & Solution
Correct Answer
(A) \(\log _{e} 4\)
Step-by-step Solution
Detailed explanation
We have, \(\int_{\log 2}^{x} \frac{1}{\sqrt{e^{y}-1}} d y=\frac{\pi}{6}\) Let \(\quad \sqrt{e^{y}-1}=t\) \(\Rightarrow \quad e^{y}-1=t^{2}\) \(\Rightarrow \quad e^{y}=1+t^{2}\) \(\Rightarrow \quad e^{y} d y=2 t d t\) \(\Rightarrow \quad\left(1+t^{2}\right) d y=2 t d t\)…
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