COMEDK · Maths · 8. Trigonometric Ratios & Identities
If \(2\sin\theta = \left(x + \dfrac{1}{x}\right)\), then \(\sin 3\theta + \dfrac{1}{2}\left(x^3 + \dfrac{1}{x^3}\right) =\)
- A \(0\)
- B \(3\)
- C \(-1\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
Given \(x + \dfrac{1}{x} = 2\sin\theta\) Cubing both sides, we get: \(\left(x + \dfrac{1}{x}\right)^3 = (2\sin\theta)^3\) \(x^3 + \dfrac{1}{x^3} + 3\left(x + \dfrac{1}{x}\right) = 8\sin^3\theta\) Substituting \(x + \dfrac{1}{x} = 2\sin\theta\):…
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