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COMEDK · Maths · 8. Trigonometric Ratios & Identities

If \(2\sin\theta = \left(x + \dfrac{1}{x}\right)\), then \(\sin 3\theta + \dfrac{1}{2}\left(x^3 + \dfrac{1}{x^3}\right) =\)

  1. A \(0\)
  2. B \(3\)
  3. C \(-1\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0\)

Step-by-step Solution

Detailed explanation

Given \(x + \dfrac{1}{x} = 2\sin\theta\) Cubing both sides, we get: \(\left(x + \dfrac{1}{x}\right)^3 = (2\sin\theta)^3\) \(x^3 + \dfrac{1}{x^3} + 3\left(x + \dfrac{1}{x}\right) = 8\sin^3\theta\) Substituting \(x + \dfrac{1}{x} = 2\sin\theta\):…