COMEDK · Maths · 21. Matrices
If \(2 A+3 B=\left[\begin{array}{ccc}2 & -1 & 4 \\ 3 & 2 & 5\end{array}\right]\) and \(A+2 B=\left[\begin{array}{lll}5 & 0 & 3 \\ 1 & 6 & 2\end{array}\right]\), then \(B=\)
- A \(\left[\begin{array}{ccc}8 & 1 & 2 \\ 1 & 10 & 1\end{array}\right]\)
- B \(\left[\begin{array}{ccc}8 & 1 & -2 \\ -1 & 10 & -1\end{array}\right]\)
- C \(\left[\begin{array}{ccc}8 & 1 & 2 \\ -1 & 10 & -1\end{array}\right]\)
- D \(\left[\begin{array}{ccc}8 & -1 & 2 \\ -1 & 10 & -1\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{ccc}8 & 1 & 2 \\ -1 & 10 & -1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
We have, \(2 A+3 B=\left[\begin{array}{ccc}2 & -1 & 4 \\ 3 & 2 & 5\end{array}\right]...(i)\) and \(A+2 B=\left[\begin{array}{lll}5 & 0 & 3 \\ 1 & 6 & 2\end{array}\right]...(ii)\) Multiply Eq. (ii) by 2 , we get…
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