COMEDK · Maths · 21. Matrices
If \(2 A+3 B=\left[\begin{array}{ccc}2 & -1 & 4 \\ 3 & 2 & 5\end{array}\right]\) and \(A+2 B=\left[\begin{array}{lll}5 & 0 & 3 \\ 1 & 6 & 2\end{array}\right]\) then \(B=\)
- A \(\left[\begin{array}{ccc}
8 & -1 & 2 \\
-1 & 10 & -1
\end{array}\right]\) - B \(\left[\begin{array}{ccc}
-8 & -1 & -2 \\
1 & -10 & 1
\end{array}\right]\) - C \(\left[\begin{array}{ccc}
8 & 1 & -2 \\
-1 & 10 & -1
\end{array}\right]\) - D \(\left[\begin{array}{ccc}
8 & 1 & 2 \\
-1 & 10 & -1
\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{ccc}
8 & 1 & 2 \\
-1 & 10 & -1
\end{array}\right]\)
Step-by-step Solution
Detailed explanation
Let \(M_1 = 2A + 3B = \begin{bmatrix} 2 & -1 & 4 \\ 3 & 2 & 5 \end{bmatrix}\) and \(M_2 = A + 2B = \begin{bmatrix} 5 & 0 & 3 \\ 1 & 6 & 2 \end{bmatrix}\). We want to find \(B\). Multiply the second equation by \(2\):…
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