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COMEDK · Maths · 23. Inverse Trigonometric Functions

If \(\cos ^{-1} x=\alpha,(0 < x < 1)\) and \(\sin ^{-1}\left(2 x \sqrt{1-x^{2}}\right)+\sec ^{-1}\left(\frac{1}{2 x^{2}-1}\right)=\frac{2 \pi}{3}\), then \(\tan ^{-1}(2 x)=\)

  1. A \(\frac{\pi}{2}\)
  2. B \(\frac{\pi}{3}\)
  3. C \(\frac{\pi}{4}\)
  4. D \(\frac{\pi}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\pi}{3}\)

Step-by-step Solution

Detailed explanation

Given that, \(\cos ^{-1} x=\alpha,(0 < x < 1)...(i)\) \(\Rightarrow \quad x=\cos \alpha\) Thus, \(\sin ^{-1}\left(2 x \sqrt{1-x^{2}}\right)+\sec ^{-1}\left(\frac{1}{2 x^{2}-1}\right)=\frac{2 \pi}{3}\)…