COMEDK · Maths · 35. Linear Programming
Given \(Z=80 x+120 y\), subject to constraints are \(x+3 y \leq 30 ; 3 x+4 y \leq 60 ; x \geq 0 ; y \geq 0\).
P is one of the corner points of the feasible region for the given Linear Programming Problem.
Then the coordinate of P is
- A \((0,15)\)
- B \((30,0)\)
- C \((6,12)\)
- D \((20,0)\)
Answer & Solution
Correct Answer
(D) \((20,0)\)
Step-by-step Solution
Detailed explanation
The constraints are \(x + 3y \leq 30\), \(3x + 4y \leq 60\), \(x \geq 0\), and \(y \geq 0\). First, identify the intersection points of the boundary lines with the axes: For \(x + 3y = 30\): If \(x = 0\), \(y = 10\). Point is \((0, 10)\). If \(y = 0\), \(x = 30\). Point is…
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