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COMEDK · Maths · 26. Differentiation

Given \(y=\tan ^{-1} x\), then \(\dfrac{d^2 y}{d x^2}\) in terms of ' \(y\) ' is

  1. A \(-2 \sin y \cos ^2 y\)
  2. B \(-\cos 2 y \sin ^2 y\)
  3. C \(-\sin 2 y \cos y\)
  4. D \(-\sin 2 y \cos ^2 y\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-\sin 2 y \cos ^2 y\)

Step-by-step Solution

Detailed explanation

Given \(y = \tan^{-1} x\), we have \(x = \tan y\). Differentiating both sides with respect to \(x\), we get \(\dfrac{dy}{dx} = \dfrac{1}{1 + x^2}\). Substituting \(x = \tan y\), we obtain \(\dfrac{dy}{dx} = \dfrac{1}{1 + \tan^2 y} = \dfrac{1}{\sec^2 y} = \cos^2 y\). Now,…