COMEDK · Maths · 34. Three Dimensional Geometry
Given that the lines \(L_1: \vec{r}=\hat{\imath}+\hat{\jmath}-\hat{k}+\lambda(3 \hat{\imath}-\hat{\jmath})\) and
\(L_2: \vec{r}=4 \hat{\imath}-\hat{k}+\mu(2 \hat{\imath}+3 \hat{k})\)
are neither skew nor parallel. Then the shortest distance between the lines is
- A 0 unit
- B \(\sqrt{94}\) unit
- C \(\sqrt{26}\) unit
- D \(\sqrt{5}\) unit
Answer & Solution
Correct Answer
(A) 0 unit
Step-by-step Solution
Detailed explanation
The lines are given by \(L_1: \vec{r} = \vec{a}_1 + \lambda \vec{b}_1\) and \(L_2: \vec{r} = \vec{a}_2 + \mu \vec{b}_2\), where \(\vec{a}_1 = \hat{i} + \hat{j} - \hat{k}\), \(\vec{b}_1 = 3 \hat{i} - \hat{j}\), \(\vec{a}_2 = 4 \hat{i} - \hat{k}\), and…
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