COMEDK · Maths · 10. Straight Lines
For what value of \(\mathrm{a}\) and \(\mathrm{b}\) the intercepts cut off on the co-ordinate axes by the line \(a x-b y+8=0\) are equal in length but opposite in signs to those cut off by the line \(2 x-3 y+6=0\) on the axes
- A \(a=-\dfrac{8}{3} \quad b=-4\)
- B \(a=-\dfrac{8}{3} \quad b=4\)
- C \(a=\dfrac{8}{3} \quad b=4\)
- D \(a=\dfrac{8}{3} \quad b=-4\)
Answer & Solution
Correct Answer
(A) \(a=-\dfrac{8}{3} \quad b=-4\)
Step-by-step Solution
Detailed explanation
The equation of the line is \(2x - 3y + 6 = 0\). Rewriting in intercept form \(\dfrac{x}{A} + \dfrac{y}{B} = 1\): \(2x - 3y = -6 \Rightarrow \dfrac{x}{-3} + \dfrac{y}{2} = 1\). The intercepts are \(A = -3\) and \(B = 2\). The intercepts of the line \(ax - by + 8 = 0\) are equal…
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