COMEDK · Maths · 28. Indefinite Integration
For two matrices A and B , given that \(A^{-1}=\dfrac{1}{8} B\) then inverse of (8A) is
- A \(\dfrac{1}{64} B\)
- B B
- C \(\dfrac{1}{8} B\)
- D 8B
Answer & Solution
Correct Answer
(A) \(\dfrac{1}{64} B\)
Step-by-step Solution
Detailed explanation
Given the relation \(A^{-1} = \dfrac{1}{8} B\). We need to find the inverse of the matrix \((8A)\). Using the property of matrix inversion \((kA)^{-1} = \dfrac{1}{k} A^{-1}\) for any non-zero scalar \(k\), we have: \((8A)^{-1} = \dfrac{1}{8} A^{-1}\). Substituting the given…
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