COMEDK · Maths · 14. Ellipse
For the ellipse \(25 x^{2}+9 y^{2}-150 x-90 y+225=0\) the eccentricity \(e\) is equal to
- A \(\frac{2}{5}\)
- B \(\frac{3}{5}\)
- C \(\frac{4}{5}\)
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{4}{5}\)
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