COMEDK · Maths · 36. Probability
For \(k=1,2,3\) the box \(B_k\) contains ' \(k\) ' red balls and \((k+1)\) white balls. Let \(P\left(B_1\right)=\dfrac{1}{2}, P\left(B_2\right)=\dfrac{1}{3}\) and \(P\left(B_3\right)=\dfrac{1}{6}\). A box is selected at random, and a ball is drawn from it. If a red ball is drawn, then the probability that it has come from \(B_2\) is
- A \(\dfrac{14}{39}\)
- B \(\dfrac{10}{13}\)
- C \(\dfrac{35}{78}\)
- D \(\dfrac{12}{13}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{14}{39}\)
Step-by-step Solution
Detailed explanation
Let \(R\) be the event that a red ball is drawn. The probabilities of selecting the boxes are \(P(B_1) = \dfrac{1}{2}\), \(P(B_2) = \dfrac{1}{3}\), and \(P(B_3) = \dfrac{1}{6}\). The probabilities of drawing a red ball from each box are:…
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