COMEDK · Maths · 27. Application of Derivatives
Find the equations of the tangent and the normal to the curve \(y=\frac{x^{3}}{4-x}\) at \((2,4)\)
- A \(8 x+y-12=0 ; x+8 y+34=0\)
- B \(8 x-y-12=0 ; x-8 y-34=0\)
- C \(8 x+4 y+12=0, x-8 y+34=0\)
- D \(8 x-y-12=0, x+8 y-34=0\)
Answer & Solution
Correct Answer
(D) \(8 x-y-12=0, x+8 y-34=0\)
Step-by-step Solution
Detailed explanation
Given curve, \(y=\frac{x^{3}}{4-x}...(i)\) is the given curve Differentiating Eq. (i) w.r.t. \(x\), we get…
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